Please help guys its one of those long wordy qustions n i dont' get it:

A rectangular garden is fenced on three sides, and the house forms the fourth side of the rectangle.

Given that the total length og the fence is 80m show that the area, A, of the gardens is given be the formula A= y (80- 2y), where y is the distance from the house to the end of the garden.

Please help....thanx!

as you can see in the attachment, there's the house and the 3 lines are the fence...

means:
80 = y + y + x
80 = 2y + x
x = 80 - 2y

Area of rectangle = xy
                         = (80-2y)y

eeh...no need differentiation ler...

you can look for some past papers !!

www.freeexampapers.com

i think, you can find many problems, where you can solve them !!

this improves your practice.

1. Do not "hijack" someone else's thread to ask a completely new question- start your own thread.

2. Show us what you have done, what you have attempted.

You know that any line passing through (1,0) must be of the form y= m(x-1).
What are the conditions on m so that it is tangent to both curves (at some points on those curves)?


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